Question

Найти производную функции
x^2 +xy+y^2=6

Answer 1

$x^2+xy+y^2=6\\\\2x+(1\cdot y+x\cdot y')+2yy'=0\\\\2x+y+xy'+2yy'=0\\\\y'\, (x+2y)=-2x-y\\\\y'=-\frac{2x+y}{x+2y}$

Answer 2

x² +xy+y²=6

2х+у+х*у'+2y*y'=0

у'(x+2y)=-2x-y

у'=(-2x-y)/(x+2y)