Question

ПОМОГИТЕ ДАЮ 100 БАЛЛОВ ​

Answer 1

Ответ:

$\frac{1}{3} \times (2 \frac{2}{15} \times 6 \frac{1}{4} - 5 \frac{1}{3} \times 1 \frac{1}{8} ) + 4 \frac{5}{9} = \\ \frac{1}{3} \times ( \frac{32}{15} \times \frac{25}{4} - \frac{16}{3} \times \frac{9}{8} ) + 4 \frac{5}{9} = \\ \frac{1}{3} \times ( \frac{8}{3} \times \frac{5}{1} - \frac{2}{1} \times \frac{3}{1} ) + 4 \frac{5}{9} = \\ \frac{1}{3} \times ( \frac{40}{3} - 6) + 4 \frac{5}{9} = \\ \frac{1}{3} \times (13 \frac{1}{3} - 6) + 4 \frac{5}{9} = \\ \frac{1}{3} \times \frac{28}{3} + 4 \frac{5}{9} = \frac{28}{9} + 4\frac{5}{9} = \\ 3 \frac{1}{9} + 4 \frac{5}{9} = 7 \frac{6}{9} = 7 \frac{2}{3}$

Answer 2

Переводим смешанные дроби в неправильные:

1) $\frac{1}{3} * (\frac{32}{15} * \frac{25}{4} - \frac{16}{3} * \frac{9}{8}) + \frac{41}{9} = 7$

1. $\frac{32}{15} * \frac{25}{4} = \frac{40}{3}$

2. $\frac{16}{3} * \frac{9}{8} = \frac{6}{1}$

3. $\frac{40}{3} - \frac{6}{1} = \frac{40}{3} - \frac{18}{3} = \frac{22}{3}$

4. $\frac{1}{3} * \frac{22}{3} = \frac{22}{9}$

5. $\frac{22}{9} + \frac{41}{9} = \frac{63}{9} = 7$

2) $\frac{154}{5} - \frac{7}{5} * (\frac{9}{5}(\frac{151}{12} - \frac{343}{36}) - \frac{17}{35} * \frac{45}{34}) = 24$

1. $\frac{151}{12} - \frac{343}{36} = \frac{453}{36} - \frac{343}{36} = \frac{110}{36}$

2. $\frac{9}{5} * \frac{110}{36} = \frac{22}{4}$

3. $\frac{17}{35} * \frac{45}{34} = \frac{9}{14}$

4. $\frac{22}{4} - \frac{9}{14} = \frac{154}{28} - \frac{18}{28} = \frac{136}{28}$

5. $\frac{7}{5} * \frac{136}{28} = \frac{136}{20}$

6. $\frac{154}{5} - \frac{136}{20} = \frac{616}{20} - \frac{136}{20} = \frac{480}{20} = 24$