Question

помогите...................................................................

Answer 1

$(x^2-3)(x+2y^2)=x^2*x+2x^2*y^2-3x-3*2y^2=\\=x^3+2x^2y^2-3x-6y^2$

Answer 2

(х²-3)*(х+2у²)=х²*х+х²*2у²-3*х-3*2у²=х³+2х²у²-3х-6у²