Question

Помогите пожалуйста! 35 баллов​

Answer 1

$2\cdot 4^{log_44}=2\cdot 4=8\\\\16^{log_43}=4^{2log_43}=4^{log_43^2}=4^{log_49}=9\\\\log_{0,5}64=-log_22^6=-6\\\\log_216=log_22^4=4\\\\(log_8512)\cdot (log_232)=log_{2^3}2^9\cdot log_22^5=\frac{9}{3}\cdot 5=15\\\\log_{12}252-log_{12}1,75=log_{12}\frac{252}{1,75}=log_{12}144=log_{12}12^2=2\\\\log_55+log_{0,25}64=1+log_{2^{-2}}2^6=1+(\frac{6}{-2})=1-3=-2\\\\ log_{1,8}5-log_{1,8}9=log_{1,8}\frac{5}{9}=log_{\frac{9}{5}}(\frac{9}{5})^{-1}=-1\\\\log_{0,8}3\cdot log_31,25=log_{\frac{4}{5}}3\cdot log_3\frac{5}{4}=\frac{log_3\frac{5}{4}}{log_3\frac{4}{5}}=\frac{log_3(\frac{4}{5})^{-1}}{log_3\frac{4}{5}}=-1\\\\\frac{log_910}{log_911}+log_{11}0,1=log_{11}10+log_{11}10^{-1}=log_{11}10-log_{11}10=0$