Question

СРОЧНО
$(frac{a+3}{a-3} - frac{a-3}{a+3} + frac{36}{a^{2}-9 }) / frac{6}{a-3}$

Answer 1

$(frac{a+3}{a-3} - frac{a-3}{a+3} + frac{36}{a^{2}-9 }) : frac{6}{a-3} =(frac{(a+3)^2-(a-3)^2+36}{a^2-9}):frac{6}{a-3}=\=(frac{a^2+6a+9-a^2+6a-9+36}{a^2-9})*frac{a-3}{6}=frac{12*(a+3)}{(a-3)(a+3)}*frac{a-3}{6}=2$