Question

8^(-1/3)*16^(1/3)/2^(-1/3)

Answer 1

$\frac{8^{-\frac{1}{3}}\cdot 16^{\frac{1}{3}}}{2^{-\frac{1}{3}}}=\frac{2^{\frac{1}{3}}\cdot 2^{\frac{4}{3}}}{2^{\frac{3}{3}}}=\frac{2^{\frac{5}{3}}}{2}=2^{\frac{2}{3}}=\sqrt[3]{4}$