Question

tg^2α+sin^2α+cos^2α
Упростить выражение​

Answer 1

$tg^{2}\alpha+Sin^{2}\alpha+Cos^{2}\alpha=tg^{2}\alpha +(Sin^{2}\alpha +Cos^{2}\alpha)=tg^{2}\alpha+1=\frac{1}{Cos^{2}\alpha}$