Question

Ребятки помогите решить

а ($\sqrt{5} +\sqrt{2})^{2}$

б $(\sqrt{y} - z)*(\sqrt{y}+z )$

в $(\sqrt{7} + 2\sqrt{3} )*(2\sqrt{3} -\sqrt{7} )$

г $(5-3\sqrt{2})^{2}+6\sqrt{50}$

Answer 1

$1)(\sqrt{5}+\sqrt{2})^{2}=(\sqrt{5}){^{2}+2*\sqrt{5}*\sqrt{2}+(\sqrt{2})^{2}=5+2\sqrt{10}+2=7+2\sqrt{10}} \\\\2)(\sqrt{y}-z)*(\sqrt{y}+z)=(\sqrt{y})^{2}-z^{2}=y-z^{2}\\\\3)(\sqrt{7}+2\sqrt{3} )*(2\sqrt{3}-\sqrt{7})=(2\sqrt{3} )^{2}-7^{2}=12-49=-37\\\\4)(5-3\sqrt{2})^{2}+6\sqrt{50}=5^{2}-2*5*3\sqrt{2}+(3\sqrt{2})^{2}+6\sqrt{25*2}=25-30\sqrt{2}+18+30\sqrt{2}=25+18=43$