Question

Решите пожалуйста - даю 10 баллов

Answer 1

1)При x=-8;y=0.1

$\frac{x-6y^2}{2y} =\frac{-8-6*0.1^2}{2*0.1} =\frac{-8-6*0.01}{0.2} =\frac{-8-0,06}{0.2} =\frac{-8,06}{0.2} =-\frac{8,06}{0.2}=-40,3$

Если При x=8 ;y=0.1

$\frac{x-6y^2}{2y}=\frac{8-6*0,1^2}{2*0.1}=\frac{8-6*0.01}{0.2} =\frac{8-0.06}{0.2} =\frac{7,94}{0.2} = 39,7$

2)При a=0.2 ;b=-5

$\frac{a^2-b}{a} =\frac{0,2^2-(-5)}{0,2} =\frac{0,04+5}{0,2} =\frac{5,04}{0,2} =25,2$