Question

а) (1/4)^(2-1,5х)=1

б) 0,7^(9-8х)=10/7

Answer 1

$(1/4)^{2-1,5x}=1\\(1/4)^{2-1,5x}=(1/4)^0\\2-1,5x=0\\1,5x=2\\x=\frac{4}{3}\\x=1\frac{1}{3}\\\\(0,7)^{9-8x}=\frac{10}{7}\\(0,7)^{9-8x}=(\frac{7}{10})^{-1}\\(0,7)^{9-8x}=(0,7)^{-1}\\9-8x=-1\\ 8x=9+1\\8x=10\\x=1,25$