Question

Помогите Решить с обьяснениям ✔️

Answer 1

$\frac{7-x}{5-x}=\frac{x-3}{5-x}\\\\\left \{ {{7-x=x-3} \atop {5-x\neq0}} \right.\\\\\left \{ {{-x-x=-3-7} \atop {x\neq5 }} \right.\\\\-2x=-10\\\\x=5-neyd$

Ответ : корней нет

$2)\frac{2}{x-5}+\frac{1}{x+5}=\frac{3}{x}\\\\\frac{2}{x-5}+\frac{1}{x+5}-\frac{3}{x}=0\\\\\frac{2*x*(x+5)+x*(x-5)-3(x-5)(x+5)}{x(x-5)(x+5)}=0\\\\\frac{2x^{2}+10x+x^{2}-5x-3x^{2}+75}{x(x-5)(x+5)}=0\\\\\frac{5x+75}{x(x-5)(x+5)}=0\\\\\frac{5(x+15)}{x(x-5)(x+5)}=0\\\\\left \{ {{x+15=0} \atop {x\neq0;x-5\neq0;x+5\neq0 }} \right.\\\\\left \{ {{x=-15} \atop {x\neq0,x\neq 5;x\neq-5}} \right.\\\\Otvet:\boxed{-15}$