Question

$frac{x}{x-2}-frac{8}{x+5}=frac{14}{x^{2}+3x-10}$

Answer 1

$frac{x}{x-2}-frac{8}{x+5}= frac{14}{(x-2)(x+5)}\ frac{ x(x+5)-8(x-2)}{(x-2)(x+5)}=frac{14}{ (x-2)(x+5)}\ x^2+5x-8x+16=14\ x^2-3x+2 = 0\ D=9-4*1*2=1^2\ x_{1}=frac{3+1}{2}=2\ x_{2}=frac{3-1}{2}=1$