Question

Обчислить нужно
Помогите, с.р на пн!!
Срочно, даю 35 балов​

Answer 1

Ответ:

1.

$8^{ - 3} = (\frac{1}{8})^{3} = \frac{1}{512}$

2.

$( \frac{1} {5})^{ - 3} ={5}^{3} = 125$

3.

$( - 4)^{ - 2} = (- \frac{1}{4})^{2} = \frac{1}{16}$

4.

$(9 \frac{2}{7})^{0} = 1$

5.

$( \frac{5}{9})^{ - 4} \div ( \frac{5}{9})^{ - 6} =( \frac{5}{9} )^{ - 4 - ( - 6)} = ( \frac{5}{9})^{2} = \frac{25}{81}$

6.

$( - 15)^{ - 1} = - \frac{1}{15}$

7.

$(0.6)^{ - 2} = (\frac{6}{10})^{ - 2} = ( \frac{10}{6})^{2} = \frac{100}{36} = \frac{25}{9} = 2 \frac{7}{9}$

8.

$(1 \frac{1}{7} )^{ - 2} = (\frac{8}{7})^{ - 2} = ( \frac{7}{8})^{2} = \frac{49}{64}$

9.

$8^{ - 8} \times 8^{6} = 8^{ - 8 + 6} = 8^{ - 2} = ( \frac{1}{8})^{2} = \frac{1}{64}$

10.

$5^{ - 3} \div 5^{ - 4} = 5^{ - 3 - ( - 4)} = 5^{1} = 5$

11.

$(( \frac{1}{2})^{ - 2})^{ - 1} = ( \frac{1}{2})^{ - 2 \times ( - 1)} = (\frac{1}{2})^{2} = \frac{1}{4} = 0.25$

12.

$(0.3)^{ - 3} = ( \frac{3}{10})^{ - 3} = ( \frac{10}{3})^{3} = \frac{1000}{27} = 37 \frac{1}{27}$