Question

Помогите решить уравнение, пожалуйста!!!

Answer 1

$5^{2x+1}-5^{x}=4\\\\5*(5^{x})^{2}-5^{x}-4=0\\\\5^{x}=m,m>0\\\\5m^{2}-m-4=0\\\\D=(-1)^{2}-4*5*(-4)=1+80=81=9^{2}\\\\m_{1}=\frac{1+9}{10}=1\\\\m_{2}=\frac{1-9}{10}=-0,8<0-neyd\\\\5^{x}=1\\\\5^{x}=5^{0}\\\\x=0$