Question

6 класс, математика, задачи 6, 7, 8

Answer 1

7.

BOC=FOE=70°

AOC=AOB+BOC=50+70=130°

BOD=AOD-AOB=180-50=130°

COD=180-AOB-BOC=180-50-70=60°

COE=COD+DOE=60+50=110°

AOB=50° FOE=70° BOC=70°

COD=60° DOE=50° AOF=60°

ОТВЕТ:

AOE=130°

FOD=120°

BOF=110°

AOF=60°

8.

८.KOM=U.KM=60°

U.MN=(KN+KM+MN)-U.KN-U.KM=U.MN

U.MN=360-240-60=60°

U.MN=८.MON=60°

Ответ: U.MN=60°