Question

Срочно! Задание номер 2 и 4!

Answer 1

$2)\frac{5^{4}*0,2^{-2}}{125^{2}}=\frac{5^{4}*(\frac{1}{5})^{-2}}{(5^{3})^{2}}=\frac{5^{4}*5^{2}}{5^{6}}=\frac{5^{6}}{5^{6}}=1$

$4)(\frac{b+1}{b-1}-\frac{b}{b+1}):\frac{3b+1}{2b-2}=\frac{b^{2}+2b+1-b^{2}+b}{(b-1)(b+1)}*\frac{2(b-1)}{3b+1}=\frac{(3b+1)*2}{(b+1)(3b+1)}=\frac{2}{b+1}$