Question

(14y+1)⋅(2y−4)=(28y−5)(y+1) памагитиииииии

Answer 1

Ответ:

28y² - 56y + 2y - 4 = 28y² + 28y - 5y -5

28y² - 54y -4 = 28y² + 23y - 5

28y² - 28y² -54y - 23y -4 +5 = 0

-77y +1 = 0

77y = 1

y = 1/77