Question

функция задана формулой у = 7/x. Заполните пропуски.

y(1) =

y(-1/2) =

y(5) =

y(0.3) =

y(-7) =

y(49) =

Answer 1

Ответ:

$y(1) = \frac{7}{1} = 7 \\ y( - \frac{1}{2} ) = \frac{7}{ - \frac{1}{2} } = - 14 \\ y(5) = \frac{7}{5} = 1.4 \\ y(0.3) = \frac{7}{0.3 } = \frac{70}{3} = 23.(3) \\ y( - 7) = \frac{7}{ - 7} = - 1 \\ y(49) = \frac{7}{49} = \frac{1}{7} = 0.(142857)$