Question

3,3(5)
7,8(1)
9,6(15)
10,7(36)
9,13(72)
10,25(18)
11,24(36)

Answer 1

3,3(5) = $\frac{151}{45} = 3\frac{16}{45}$

7,8(1) = $\frac{703}{90} = 7\frac{73}{90}$

9,6(15)  = $\frac{9519}{990} = 9\frac{609}{990}$

10,7(36)  = $\frac{10629}{990} = 10\frac{729}{990}$

9,13(72)  = $\frac{90459}{9990} = 9\frac{1359}{9990}$

10,25(18)  = $\frac{101493}{9990} = 10\frac{2493}{9990}$

11,14(36) = $\frac{55161}{4950} = 11\frac{711}{4950}$