Question

Решите неравенства:
$\sqrt{9 + x} < 4$
$\sqrt{1 + x} < 2$
​

Answer 1

1.

{9+x >= 0; x >= -9

{9+x < 16

x < 7

x€[-9; 7)

2.

{1+x >= 0; x >= -1

{1+x < 4

x < 3

x€[-1; 3)