Question

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Answer 1

1) $(2\frac{13}{48} + 2\frac{5}{12}) : 3\frac{3}{4} - 9\frac{3}{4}:12=(\frac{109}{48}+\frac{29}{12}):\frac{15}{4}-\frac{39}{4}:12=(\frac{109}{48}+\frac{116}{48}):\frac{15}{4}-\frac{39}{4}*\frac{1}{12}=\frac{225}{48}*\frac{4}{15}-\frac{39}{48}=\frac{15}{12}-\frac{39}{48}=\frac{60}{48}-\frac{39}{48}=\frac{21}{48}=\frac{21}{48}=\frac{7}{16}$

2) $(8:2\frac{10}{19}- 1\frac{13}{15}* 1\frac{6}{49}):(3\frac{1}{12}-1\frac{25}{36})=(8:\frac{48}{19}- \frac{28}{15}* \frac{55}{49}):(\frac{37}{12}-\frac{61}{36})=(8*\frac{19}{48}- \frac{4}{3}* \frac{11}{7}):(\frac{111}{36}-\frac{61}{36})=(\frac{19}{6}- \frac{44}{21}):\frac{50}{36}=(\frac{133}{42}- \frac{88}{42}):\frac{25}{18}=\frac{45}{42}:\frac{25}{18}=\frac{15}{14}*\frac{18}{25}=\frac{3}{7}*\frac{9}{5}=\frac{27}{35}$