Question

Помогите с математикой, даю 20 б​

Answer 1

$1)x+2\frac{3}{13}=10\frac{8}{39} \\ \\ x=10\frac{8}{39}-2\frac{3}{13}\\ \\ 10\frac{8}{39}-2\frac{3*3}{13*3}=10\frac{8}{39}-2\frac{9}{39}=7\frac{38}{39} \\ \\ x=7\frac{38}{39}$

$2)y+8\frac{7}{12}=10\frac{5}{24}\\ \\ y=10\frac{5}{24}-8\frac{7}{12} \\ \\ 10\frac{5}{24}-8\frac{7*2}{12*2}=9\frac{29}{24}-8\frac{14}{24}=1\frac{15}{24}=1\frac{5}{8}\\ \\ y=1\frac{5}{8}$

$3)x+14\frac{2}{9}=38\frac{1}{18} \\ \\ x=38\frac{1}{18}-14\frac{2}{9} \\ \\38\frac{1}{18}-14\frac{2*2}{9*2}=37\frac{19}{18}-14\frac{4}{18}=23\frac{15}{18}=23\frac{5}{6} \\ \\ x=23\frac{5}{6}$

$4)y+3\frac{7}{11}=9\frac{3}{22} \\ \\ y=9\frac{3}{22}-3\frac{7}{11} \\ \\ 9\frac{3}{22}-3\frac{7*2}{11*2}=8\frac{25}{22}-3\frac{14}{22} =5\frac{11}{22} =5\frac{1}{2}\\\\ y=5\frac{1}{2}$