Question

выполните сложения номер 542 чётные числа​

Answer 1

$1) 3 \frac{1}{15} + 2 \frac{7}{25} = (3+2) + (\frac{1}{15} + \frac{7}{25}) = 5 + \frac{1*5+7*3}{75} = 5 \frac{5+21}{75} = 5 \frac{26}{75}$

$2) 2 \frac{7}{10} + 9 \frac{2}{15} = (2+9) + (\frac{7}{10} + \frac{2}{15}) = 11 + \frac{7*3+2*2}{30} = 11 + \frac{21+4}{30} = 11 \frac{25}{30} = 11 \frac{5}{6}$

$3) 9 \frac{5}{18} + 6 \frac{1}{12} = (9+6) + (\frac{5}{18} + \frac{1}{12}) = 15 + \frac{5*2+1*3}{36} = 15 + \frac{10+3}{36} = 15 \frac{13}{36}$

$4) 1 \frac{7}{12} + 3 \frac{5}{9} = (1+3) + (\frac{7}{12} + \frac{5}{9}) = 4 + \frac{7*3+5*4}{36} = 4 + \frac{21+20}{36} = 4 \frac{41}{36} = 5 \frac{5}{36}$

$5) 5 \frac{5}{24} + 2 \frac{1}{6} = (5+2) + (\frac{5}{24} + \frac{1}{6}) = 7 + \frac{5+1*4}{24} = 7 + \frac{5+4}{24} = 7 \frac{9}{24} = 7 \frac{3}{8}$

$6) 3 \frac{1}{12} + 4 \frac{2}{15} = (3+4) + (\frac{1}{12} + \frac{2}{15}) = 7 + \frac{1*5+2*4}{60} = 7 + \frac{5+8}{60} = 7 \frac{13}{60}$