Question

Задание 5
Вычислите
.

Answer 1

$( \frac{1}{6 - \sqrt{2} } ) \times 34 \sqrt{2} = ( \frac{6 + \sqrt{2} }{34} - \frac{6 - \sqrt{2} }{34} ) \times 34 \sqrt{2} = \frac{6 + \sqrt{2} - (6 - \sqrt{2}) }{34} \times 34 \sqrt{2} = \frac{6 + \sqrt{2} - 6 + \sqrt{2} }{34} \times 34 \sqrt{2} = \frac{2 \sqrt{2} }{34} \times 34 \sqrt{2} = \frac{ \sqrt{2} }{17} \times 34 \sqrt{2} = \sqrt{2} \times 2 \sqrt{2} = 2 \times 2 = 4$

ответ 4