Question

АЛГЕБРА!!дам 85 баллов​

Answer 1

Ответ:

Объяснение:

$(9^{-\frac{1}{4}}+(2\sqrt{2})^{-\frac{2}{3}})(\sqrt[4]{9^{-1}}-(2\sqrt{2})^{-\frac{2}{3}})=\\=(9^{-\frac{1}{4}}+(2\sqrt{2})^{-\frac{2}{3}})(9^{-\frac{1}{4}}-(2\sqrt{2})^{-\frac{2}{3}})=\\=(9^{-\frac{1}{4}})^2-(2\sqrt{2})^{-\frac{2}{3}*2}=9^{-\frac{1}{2}}-2^{\frac{3}{2}*-\frac{4}{3}}=\\=\frac{1}{3}-2^{-2}=\frac{1}{3}-\frac{1}{4}=\frac{1}{12}$

Справочно:

$2\sqrt{2}=2*2^{\frac{1}{2}}=2^{1+\frac{1}{2}}=2^\frac{3}{2}$