Question

помогите ааааааааааааа​

Answer 1

Вроде так:

$2x^{2} -x-6\leq 0\\2x^{2} +3x-4x-6\leq 0\\x*(2x+3)-2(2x+3)\leq 0\\(2x+3)*(x-2)\leq 0\\\left \{ {{2x+3\leq 0 } \atop {x-2\geq 0}} \right. \\\left \{ {{2x+3\geq 0} \atop {x-2\leq 0}} \right. \\\left \{ {{x\leq-\frac{3}{2}  } \atop {x\geq 2}} \right. \\\left \{ {{x\geq-\frac{3}{2} } \atop {x\leq 2}} \right.$

x∈∅$[-\frac{3}{2},2]$

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$x^{2} -49>0\\x^{2}>49\\|x|>7\\x>7,x\geq 0\\-x>7,x<0$

x∈{7,+∞}

x<-7,x<0}

x∈{7,+∞}

x∈{-∞,-7}

x∈{-∞,-7}∪{7+∞}

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$x^{2} <-6x\\x^{2}+6x<0\\x*(x+6)<0\\\left \{ {{x<0} \atop {x+6>0}} \right. \\\left \{ {{x>0} \atop {x+6<0}} \right.$

x∈{-6,0}

x∈∅

x∈{-6,0}