Question

задача на фото, решите номер 270 пж ​

Answer 1

$1)12a^{2}*5a^{3}b^{7}=12*5*a^{2+3}*b^{7}=60a^{5}b^{7}\\\\2)-4m^{3}*0,25m^{6}=-4*\frac{1}{4}*m^{3+6}=-m^{9}\\\\3)3ab*(-17a^{2}b)=3*(-17)*a^{1+2}b^{1+1}=-51a^{3}b^{2}\\\\4)56x^{5}y^{14}*\frac{2}{7}x^{2}y=56*\frac{2}{7}*x^{5+2}y^{14+1}=16x^{7}y^{15}\\\\5)-\frac{1}{3}p^{2}*(-27k)*5pk=-\frac{1}{3}*(-27)*5*p^{2+1}k^{1+1}=45p^{3}k^{2}\\\\6)2\frac{1}{4}b^{2} c^{5}d^{3}*(-3\frac{1}{3}b^{3}c^{4}d^{7})=\frac{9}{4}*(-\frac{10}{3})*b^{2+3}*c^{5+4}*d^{3+7}=-7,5b^{5}c^{9}d^{10}$