Question

35 баллов!!!! Решите пожалуйста!!!!!!!

Answer 1

a)

$(-\frac{16x^{2}}{27y^{3}})^{2}(\frac{9y^{2}}{8x^{2}})^{3}=\frac{8^{2}*2^{2}*x^{4}*9^{3}*y^{6}}{9^{2}*3^{2}*y^{6}*8^{3}*x^{6}}=\frac{1}{2x^{2}}$

б)

$1)\frac{\frac{1}{a}+\frac{1}{b+c}}{\frac{1}{a}-\frac{1}{b+c}}=\frac{\frac{b+c+a}{a(b+c)} }{\frac{b+c-a}{a(b+c)}}=\frac{(b+c+a)*a(b+c)}{a(b+c)*(b+c-a)}=\frac{b+c+a}{b+c-a}\\\\2)1+\frac{b^{2}+c^{2}-a^{2}}{2bc}=\frac{(b^{2}+2bc+c^{2})-a^{2}}{2bc}=\frac{(b+c)^{2}-a^{2}}{2bc} =\frac{(b+c-a)(b+c+a)}{2bc}$

$3)\frac{b+c+a}{b+c-a}*\frac{(b+c-a)(b+c+a)}{2bc}=\frac{(b+c+a)^{2}}{2bc}$

Answer 2

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