Question

8(x-2)(x^2-1) = (4x^2-2x 1)(2x 1)

Answer 1

$8x^{3}-8x-16x^{2}+16=8x^{3}+4x^{2}-4x^{2}-2x+2x+1$

$-16x^{2}-8x+15=0$

$D=64-4*(-16)*15=1024$

$x_1=frac{8+32}{-32}=-1,25$

$x_2=frac{8-32}{-32}=0,75$