Предмет: Геометрия, автор: vladaDiamond1Q1

Даны точки A(0; 4; 0), B(2; 0; 0), C(4; 0; 4), D(2; 4; 4). Докажите, что ABCD ромб

С рисунком , если можно

Ответы

Автор ответа: Ignorenko
2

Ответ:

Объяснение:

Координаты конца складываем с координатами начала,то есть

А+С

B+D

AC (4,4,4)

BD (0,4,4)

AC*BD=4+16+16=36

ABCD не ромб т.к произведение двух векторов должно равняться нулю


dnepr1: Ошибка в решении: AC (4,-4,4). Тогда AC*BD=0-16+16=0. Ещё надо доказать равенство сторон.
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