Question

Г) (3х-1)(х+2)/3 - (2х-1)^2/3 = 4 1/6 - (х+7)^2/2​

Answer 1

$Г) \frac{(3x - 1)(x + 2)}{3} - \frac{ {(2x - 1)}^{2} }{3} = 4 \frac{1}{6} - \frac{ {(x + 7)}^{2} }{2} \\ \frac{2((3x - 1)(x + 2) -{(2x - 1)}^{2})}{6} = \frac{25 - {3(x + 7)}^{2} }{6} \\ 2(3x - 1)(x + 2) -2{(2x - 1)}^{2} = 25 - {3(x + 7)}^{2} \\ 2(3x - 1)(x + 2) -2{(2x - 1)}^{2} - 25 + {3(x + 7)}^{2} = 0 \\ 18 {x}^{2} + 10x - 4 - 8{x}^{2} + 8x - 2- 25 + 3 {x}^{2} + 42x + 147 = 0 \\ 13 {x}^{2} + 60x + 116 = 0 \\ d = 3600 - 6032 = - 2132 < 0 \\ Корней \: нет$