Question

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Answer 1

sin²x = 1-cos2x/2

1-cos2x = 1+cosx

cosx+cos2x = 0

2cos3x/2•cosx/2 = 0

1)cos3x/2 = 0

3x/2 = π/2 + πk

x = π/3 + 2πk/3

k€Z

2)cos x/2

x/2 = π/2 + πn

x = π+2πn

n€Z