Question

Помогите решить Б и А

Answer 1

Ответ:

а)

$1)\frac{(2 \times 3) {}^{16} }{6 {}^{16} } = \frac{6 {}^{16} }{6 {}^{16} } = 1 \\ 2) \frac{(3 {}^{5}) {}^{6} \times 3 {}^{4} }{3 {}^{29} } = 3 {}^{30} \times 3 {}^{4} \div 3 {}^{29} = 3 {}^{30 + 4 - 29} = 3 {}^{34 - 29} = 3 {}^{5} = 243 \\ 3) \frac{(7 {}^{2}) {}^{2} \times 7 {}^{6} }{7 {}^{8} } = 7 {}^{4} \times 7 {}^{6} \div 7 {}^{8} = 7 {}^{4 + 6 - 8} = 7 {}^{2} = 49$