Question

решите пж 1)(х⁵)²×( х²×х)⁴ 2)(-х⁵)⁴×(-х⁴)⁵÷(-х³×х⁷)³​

Answer 1

$1)\; \; (x^5)^2\cdot (x^2\cdot x)^4=x^{10}\cdot (x^3)^4=x^{10}\cdot x^{12}=x^{22}\\\\\\2)\; \; (-x^5)^4\cdot (-x^4)^5\, :\, (x^3\cdot x^7)^3=x^{20}\cdot (-x^{20})\, :\, (x^{10})^3=\frac{-x^{40}}{x^{30}}=-x^{10}$