Question

16-x^2=15
7+x^2=3
1\2x^2=8
(x-4)^2=1

Answer 1

Решение:

$16-x^2=15\\x=\pm1\\7+x^2=3\\x\in\varnothing\\1/2x^2=8\\ x=\pm4\\\\(x-4)^2=1\\x=3\\x=5$

Answer 2

16 - х² = 15,

х² = 16 - 15,

х² = 1,

х = ±√1,

х1 = 1,  х2 = -1,

7 + х² = 3,

х² = 3 - 7,

х² = -4 - уравнение не имеет корней,

1/2 х² = 8,

х² = 8 * 2,

х² = 16,

х = ±√16,

х1 = 4,  х2 = -4,

(х - 4)² = 1,

х - 4 = 1,     х - 4 = -1,

х = 1 + 4,    х = -1 + 4,

х1 = 5,        х2 = 3