Question

решить систему неравенств
2х-1 > или равно 0,
12-3х>0

Answer 1

$\left \{ {{2x-1\geq0 } \atop {12-3x>0}} \right. \\\\\left \{ {{2x\geq1\ \ \ |:2 } \atop {-3x>-12\ \ \ |:(-3)}} \right.\\\\\left \{ {{x\geq\frac{1}{2} } \atop {x<4}} \right. \\\\x\in[\frac{1}{2};4)$