Question

ПОМОГИТЕ |x^2-9|+|x^2-16|=7

Answer 1

$x {}^{2} - 9 + x {}^{2} - 16 = 7 \\ x {}^{2} - 9 \geqslant 0 \\ x {}^{2} - 16 \geqslant 0 \\ - (x {}^{2} - 9) + x {}^{2} - 16 = 7 \\ x {}^{2} - 9 < 0 \\ x {}^{2} - 16 \geqslant 0 \\ x {}^{2} - 9 - (x {}^{2} + 16) = 7 \\ x {}^{2} - 9 \geqslant 0 \\ x {}^{2} - 16 < 0 \\ - (x {}^{2} - 9) - (x {}^{2} - 16) = 7 \\ x {}^{2} - 9 < 0 \\ x {}^{2} - 1 < 0 \\ x = - 4 \\ x = 4 \\ x = net \: reshenuy \\ x = vce \: chisla \\ x = - 3 \\ x = 3 \\ otvet \: x \: prinadleshit \: | - 4. - 3| |3.4|$