Question

Помогите пожалуйста, заранее спасибо!

Answer 1

Відповідь:

Пояснення:

Answer 2

Ответ:

Объяснение:

4k/(4k²-1) -(2k+1)/(6k-3) +(2k-1)/(4k+2)=(2k+1)/(12k-6)

1). 4k/(4k²-1)=4k/((2k-1)(2k+1))

2). (2k+1)/(6k-3)=(2k+1)/(3(2k-1))

3). (2k-1)/(4k+2)=(2k-1)/(2(2k+1))

4). 4k/((2k-1)(2k+1)) -(2k+1)/(3(2k-1))=12k/(3(2k-1)(2k+1)) -(2k+1)(2k+1)/(3(2k-1)(2k+1))=(12k-(2k+1)²)/(3(2k-1)(2k+1))

5). (12k-(2k+1)²)/(3(2k-1)(2k+1)) +(2k-1)/(2(2k+1))=2(12k-(2k+1)²)/(6(2k-1)(2k+1)) +3(2k-1)²/(6(2k-1)(2k+1))=(24k-2(4k²+4k+1)+3(4k²-4k+1))/(6(2k-1)(2k+1))=(24k-8k²-8k-2+12k²-12k+3)/(6(2k-1)(2k+1))=(4k+4k²+1)/(6(2k-1)(2k+1))=(2k+1)²/(6(2k-1)(2k+1))=(2k+1)/(6(2k-1))=(2k+1)/(12k-6)

(x -5x/(x+2))÷((x-3)/(x+2))-5=x-5=-3-5=-8

1). x -5x/(x+2)=(x(x+2)-5x)/(x+2)=(x²+2x-5x)/(x+2)=(x²-3x)/(x+2)=x(x-3)/(x+2)

2). (x(x-3)/(x+2))÷((x-3)/(x+2))=x(x-3)/(x+2) ·(x+2)/(x-3)=x

3). x-5=-3-5=-8