Question

СРОЧНО
Решите уравнение

Answer 1

Ответ:

$x_{1}=-3; x_{2}=3$

Объяснение:

$1-\frac{1}{2+\frac{1}{1+\frac{1}{10-x^{2} } } } =\frac{3}{5}\\ \frac{1}{2+\frac{1}{1+\frac{1}{10-x^{2} } } }=1-\frac{3}{5}=\frac{2}{5}\\2+\frac{1}{1+\frac{1}{10-x^{2} } } =\frac{5}{2}\\ \frac{1}{1+\frac{1}{10-x^{2} } }=\frac{5}{2}-2=\frac{1}{2} \\1+\frac{1}{10-x^{2} } =2\\\frac{1}{10-x^{2} }=2-1=1\\10-x^{2}=1\\x^{2}=9\\|x|=3\\x_{1}=-3; x_{2}=3$