Question

486 номер 7) 8) примеры

Answer 1

$7) \int\limits^2_1 {3sin(3x-6)} \, dx=(3\cdot(-\frac{1}{3})\cdot cos(3x-6))\bigg|^2_1=-cos(3x-6)\bigg|^2_1=\\\\ = -cos(6-6)+cos(3-6)=cos(-3)-cos0=cos3-1\\ \\ \\ 8) \int\limits^3_0 {8cos(4x-12)} \, dx=(8\cdot\frac{1}{4}\cdot sin(4x-12))\bigg|^3_0=2sin(4x-12)\bigg|^3_0=\\\\ =2sin(12-12)-2sin(0-12)=2sin0-2sin(-12)=2sin12$

Answer 2

Ответ:

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Объяснение: