Предмет: Химия, автор: GlyninaKseniya

температурный коэффициент некоторой химической реакции равен 2. при температуре 20 градусов она заканчивается за 60 секунд.за сколько секунд она закончится при 40 градусах.ПОМОГИТЕ ПОЖАЛУЙСТА, СРОЧНО.......

Ответы

Автор ответа: Obsidiana
0

Дано: Т1=20гр Т2=40гр t1=60сек коэф.хим реак=2.

Найти:t2

Решение:

скорость(V)t1=скорость(V)t2* коэф.хим реак в степени (Т2-Т1):10 

скорость(V)t1=скорость(V)t2* 2 в степени (40-20):10

Vt2=Vt1*2 в степени 2

Vt2=4*Vt1

t2=60:4=15сек

t2=15сек

то что подчеркнуто нужно писать как индекс 

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