Question

9-3(у+2)=(7у-5)*(-3)

Answer 1

$9-3(y+2)=(7y-5)\cdot(-3) \ \  \ |:(-3)\\\\-3+(y+2)=7y-5\\\\-3+y+2=7y-5\\\\y-7y=-5+3-2\\\\-6y=-4\ \ \ |:(-6)\\\\y=\frac{2}{3}$