Question

поможіть будь ласка​

Answer 1

1) (6x² - 7x + 4) - (4x² - 4x + 18) = 6x² - 7x + 4 - 4x² + 4x - 18 =

= 2x² - 3x - 14

2) (3x + 9) + (- x² - 15x - 40) = 3x + 9 - x² - 15x - 40 = - x² - 12x - 31

3) (10a² - 6a + 5) - (- 11a + a³ + 6) = 10a² - 6a + 5 + 11a - a³ - 6 =

= - a³ + 10a² - 6a - 1

4) (13xy-11x²+10y²) - (-15x²+10xy-15y²) = 13xy-11x²+10y²+15x²-10xy+15y²=

= 3xy + 5x² + 25y²

5) (14ab² - 17ab + 5a²b) + (20ab - 14a²b) =

= 14ab² - 17ab + 5a²b + 20ab - 14a²b = - 9a²b + 14ab² + 3ab

6) $(\frac{7}{8}x^{3}y^{2} -\frac{5}{6}xy^{2} )-(-\frac{7}{12}xy^{2} +\frac{5}{12}x^{3}y^{2})=\frac{7}{8}x^{3}y^{2} -\frac{5}{6}xy^{2}+\frac{7}{12}xy^{2} -\frac{5}{12}x^{3}y^{2}=\\\\=\frac{7}{8}x^{3}y^{2} -\frac{5}{12}x^{3}y^{2} -\frac{5}{6}xy^{2}+\frac{7}{12}xy^{2}=\frac{21}{24}x^{3}y^{2} -\frac{10}{24}x^{3}y^{2} -\frac{10}{12}xy^{2}+\frac{7}{12}xy^{2}=\\\\=\frac{11}{24}x^{3}y^{2} -\frac{3}{12}xy^{2}=xy^{2}*(\frac{11}{24}x^{2}  -\frac{3}{12})$