Question

(6/35-4/7)-(-1,8-4,3)-5,7=???

Answer 1

$(frac{6}{35}-frac{4}{7})-(-1,8-4,3)-5,7=</var>0$</p> <p>1) <img src=[/tex]frac{6}{35}-frac{4}{7}=frac{6-20}{35}=frac{-14}{35}=-frac{2}{5}=-0,4" title="(frac{6}{35}-frac{4}{7})-(-1,8-4,3)-5,7=0" title="frac{6}{35}-frac{4}{7}=frac{6-20}{35}=frac{-14}{35}=-frac{2}{5}=-0,4" title="(frac{6}{35}-frac{4}{7})-(-1,8-4,3)-5,7=0" alt="frac{6}{35}-frac{4}{7}=frac{6-20}{35}=frac{-14}{35}=-frac{2}{5}=-0,4" title="(frac{6}{35}-frac{4}{7})-(-1,8-4,3)-5,7=0" />

1) $(frac{6}{35}-frac{4}{7})-(-1,8-4,3)-5,7=</var>0$

1) [tex]frac{6}{35}-frac{4}{7}=frac{6-20}{35}=frac{-14}{35}=-frac{2}{5}=-0,4" />

2) -1,8-4,3=-(1,8+4,3)=-6,1

3) -0,4-(-6,1)=-0,4+6,1=6,1-0,4=5,7

4) 5,7-5,7=0

Answer 2

(6/35-4/7)-(-1,8-4,3)-5,7=(6/35-20/35)+6,1-5,7=-14/35+6,1-5,7=-0,4+0,4=0