Question

Помогите вычислить 2/3+(2 7/12-1 1/21); 3 1/3+5 4/9-2 5/6+7/18; (2 1/8-4/7)+(4 1/2-3 7/12)-3/14 пожалуйста помогите

Answer 1

$\frac{2}{3} + (2 \frac{7}{12} - 1 \frac{1}{21} ) = \frac{2}{3} + (2 \frac{49}{84} - 1 \frac{4}{84} ) = \frac{2}{3} + 1 \frac{45}{84} = \frac{56}{84} + 1 \frac{45}{84} = 1 \frac{101}{84} = 2 \frac{17}{84} \\ 3 \frac{1}{3} + 5 \frac{4}{9} - 2 \frac{5}{6} + \frac{7}{18} = 3 \frac{6}{18} + 5 \frac{8}{18} - 2 \frac{15}{18} + \frac{7}{18} = 8 \frac{21}{18} - 2 \frac{15}{18} = 6 \frac{6}{18} = 6 \frac{1}{3} \\ </p><p>(2 \frac{1}{8} - \frac{4}{7} ) + (4 \frac{1}{2} - 3 \frac{7}{12} ) - \frac{3}{14} = (2 \frac{7}{56} - \frac{32}{56} ) + (4 \frac{6}{12} - 3 \frac{7}{12} ) - \frac{3}{14} = (1 \frac{63}{56} - \frac{32}{56} ) + (3 \frac{18}{12} - 3 \frac{7}{12} ) - \frac{3}{14} = 1 \frac{31}{56} + \frac{11}{12} - \frac{3}{14} = 1 \frac{31}{56} - \frac{12}{56} + \frac{11}{12} = 1 \frac{19}{56} + \frac{11}{12} = 1 \frac{57}{168} + \frac{154}{168} = 1 \frac{211}{168} = 2 \frac{43}{168}$