Question

2 задание. Помогите пожалуйста найти x.

Answer 1

$\frac{16.5}{ \frac{1}{45} + \frac{2}{9} } = \frac{x + 1.75}{ \frac{7}{30} } \\ \frac{16.5}{ \frac{1}{45} + \frac{10}{45} } = \frac{x + 1.75}{ \frac{7}{30} } \\ \frac{16.5}{ \frac{11}{45} } = \frac{x + 1.75}{ \frac{7}{30} } \\ \frac{11}{45} (x + 1.75) = \frac{7}{30} \times 16.5 \\ x + 1.75 = \frac{7 \times 16.5}{30} \div \frac{11}{45} \\ x + 1.75 = \frac{7 \times 16.5 \times 45}{30 \times 11} \\ x + 1.75 = \frac{7 \times 16.5 \times 3}{2 \times 11} \\ x + 1.75 = \frac{346.5}{22} \\ x + 1.75 = 15.75 \\ x = 15.75 - 1.75 \\ x = 14$