Question

ПОМОГИТЕ,ПОЖАЛУЙСТА!
С ОЪЯСНЕНИЕМ^-^
ЗАРАНЕЕ СПАСИБО:)

Answer 1

$\sqrt{6+x-x^2} = 1 - x <=> \left \{ {{1-x\geq 0} \atop {6+x-x^2 = (1-x)^2}} \right. \\\\1 - x \geq 0 => x \leq 1;\\6+x-x^2 = x^2 - 2x + 1 => 2x^2 -3x - 5 = 0 => x_1 = -1, x_2 = 2.5 => x = -1\\Answer: x = -1$