Question

Вычеслить действие 1) 3/6+4/7; 2)4/11+2/3; 3)2/11+7/9; 4)7/36+2/3: со зноменателем по бестрее

Answer 1

1) 3/6 + 4/7 = 21/42 + 24/42 = 45/42 = 1 3/42 = 1 1/14

2) 4/11 + 2/3 = 12/33 + 22/33 = 34/33 = 1 1/33

3) 2/11 + 7/9 = 18/99 + 77/99 = 95/99

4) 7/36 + 2/3 = 7/36 + 24/36 = 31/36

Answer 2

Пошаговое объяснение:

$\[\begin{gathered}1)\frac{3}{6}+\frac{4}{7}=\frac{{3*7}}{{6*7}}+\frac{{4*6}}{{7*6}}=\frac{{21}}{{42}}+\frac{{24}}{{42}}=\frac{{21+24}}{{42}}=\frac{{45}}{{42}}=\frac{{15*3}}{{14*3}}=\frac{{15}}{{14}}=\boxed{1\frac{1}{{14}}} \hfill \\\\2)\frac{4}{{11}}+\frac{2}{3}=\frac{{4*3}}{{11*3}}+\frac{{2*11}}{{3*11}}=\frac{{12}}{{33}}+\frac{{22}}{{33}}=\frac{{12+22}}{{33}}=\frac{{34}}{{33}}=\boxed{1\frac{1}{{33}}} \hfill \\ \end{gathered} \]$

$\[\begin{gathered}3)\frac{2}{{11}}+\frac{7}{9}=\frac{{2*9}}{{11*9}}+\frac{{7*11}}{{9*11}}=\frac{{18}}{{99}}+\frac{{77}}{{99}}=\frac{{18+77}}{{99}}=\boxed{\frac{{95}}{{99}}} \hfill \\\\4)\frac{7}{{36}}+\frac{2}{3}=\frac{7}{{36}}+\frac{{2*12}}{{3*12}}=\frac{7}{{36}}+\frac{{24}}{{36}}=\frac{{7+24}}{{36}}=\boxed{\frac{{31}}{{36}}} \hfill \\\end{gathered} \]$