Question

ОЧЕНЬ СРОЧНО!!!!!!пожалуйста добрые люди памагите!!!!!!!​

Answer 1

$1)\frac{c^{3}}{c^{2}-8c+16}-\frac{c^{2}}{c-4}=\frac{c^{3}}{(c-4)^{2}}-\frac{c^{2}}{c-4}=\frac{c^{3}-c^{3}+4c^{2}}{(c-4)^{2}}=\frac{4c^{2}}{(c-4)^{2} } \\\\2)\frac{c^{2}}{c^{2}-16}-\frac{c}{c-4}=\frac{c^{2}}{(c-4)(c+4)}-\frac{c}{c-4}=\frac{c^{2}-c^{2}-4c}{(c-4)(c+4)}=-\frac{4c}{(c-4)(c+4)}\\\\3)\frac{4c^{2}}{(c-4)^{2}}:(-\frac{4c}{(c-4)(c+4)})=-\frac{4c^{2}}{(c-4)^{2}}*\frac{(c-4)(c+4)}{4c}=-\frac{c(c+4)}{c-4}=\frac{c^{2}+4c}{4-c}\\\\\frac{c^{2}+4c }{4-c}=\frac{c^{2}+4c}{4-c}$