Question

Log1/4(4x-3)>=-1
решите пж

Answer 1

ОДЗ :

4x - 3 > 0

4x > 3

x > 0,75

$log_{\frac{1}{4}}(4x-3)\geq-1\\\\0<\frac{1}{4}<1 \Rightarrow 4x-3\leq (\frac{1}{4})^{-1}\\\\4x-3\leq 4\\\\4x\leq7\\\\x\leq1,75\\\\Otvet:\boxed{(0,75;1,75]}$